What is the norm of #< -5 , -2, -1 >#?

1 Answer
Dec 25, 2015

Answer:

#sqrt30#

Explanation:

By definition, for any n-dimensional vector #A=(a_1,a_2,a_3,......,a_n)#, the norm is defined by
#||A||=sqrt(a_1^2+a_2^2+a_3^2+........+a_n^2)#.

So in this particular case we have a 3 dimensional vector (n = 3), and so its norm is given by

#||(-5,-2,-1)||=sqrt((-5)^2+(-2)^2+(-1)^2)#

#=sqrt30#