# What is the norm or < 8 ,-4 , 9 >?

Apr 11, 2017

The norm is $= 12.69$

#### Explanation:

The norm of a vector $\vec{a} = < p , q , r >$ is

$| | \vec{a} | | = \sqrt{{p}^{2} + {q}^{2} + {r}^{2}}$

So, we have

$| | < 8 , - 4 , 9 > | | = \sqrt{{8}^{2} + {\left(- 4\right)}^{2} + {9}^{2}}$

$= \sqrt{64 + 16 + 81}$

$= \sqrt{161}$

$= 12.69$