What is the norm or $< 8 ,-4 , 9 >$ ?

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Answer 1 · 2017-04-11T06:12:21

The norm is $=12.69$

The norm of a vector $veca= <p,q,r>$ is

$||veca||=sqrt(p^2+q^2+r^2)$

So, we have

$||<8,-4,9>||=sqrt(8^2+(-4)^2+9^2)$

$=sqrt(64+16+81)$

$=sqrt(161)$

$=12.69$

What is the norm or < 8 ,-4 , 9 >< 8 ,-4 , 9 >?