# What is the nuclear equation for the alpha decay of Po210?

${\text{_84^210Po -> }}_{82}^{206} P b {+}_{2}^{4} H e$
Po-210 has 84 protons and 126 neutrons in its nucleus. During alpha decay, an $\alpha \text{-particle}$, which is essentially a Helium-4 nucleus, is emitted by the nucleus.