What is the oxidation state of #S# in #SO_3^(2-)#?

1 Answer
Oct 5, 2017

Answer:

Let's find it out.

Explanation:

The ion shown is a sulphite ion.

Now, the oxidation state of the oxygen atoms in the ion is #-2# each.

Moreover, The sum of the oxidation states of all the atoms in a molecule or ion or in an entity accounts for the charge of the same entity to which they belong.

Let, oxidation state of the Sulphur be "#x#".

So, #color(red)(x+[3xx(-2)]=-2)#.
#:.color(red)(x+(-6)=-2)#.
#:.color(red)(x=+4)#.

So, the Oxidation state of #S# in #SO_3^(2-)# is #color(red)(+4)#. (Answer).

Hope it Helps :)