# What is the oxidation state of S in SO_3^(2-)?

Oct 5, 2017

Let's find it out.

#### Explanation:

The ion shown is a sulphite ion.

Now, the oxidation state of the oxygen atoms in the ion is $- 2$ each.

Moreover, The sum of the oxidation states of all the atoms in a molecule or ion or in an entity accounts for the charge of the same entity to which they belong.

Let, oxidation state of the Sulphur be "$x$".

So, $\textcolor{red}{x + \left[3 \times \left(- 2\right)\right] = - 2}$.
$\therefore \textcolor{red}{x + \left(- 6\right) = - 2}$.
$\therefore \textcolor{red}{x = + 4}$.

So, the Oxidation state of $S$ in $S {O}_{3}^{2 -}$ is $\textcolor{red}{+ 4}$. (Answer).

Hope it Helps :)