# What is the perimeter of a triangle with corners at (6 ,0 ), (9 ,2 ), and (5 ,4 )?

Sep 6, 2016

Perimeter is $12.2008$

#### Explanation:

To find the perimeter of a triangle with corners at $\left(6 , 0\right)$, $\left(9 , 2\right)$ and $\left(5 , 4\right)$ we need length of each of the sides, which are distance between pair of points and are

$a = \sqrt{{\left(9 - 6\right)}^{2} + {\left(2 - 0\right)}^{2}} = \sqrt{9 + 4} = \sqrt{13} = 3.6056$

$b = \sqrt{{\left(5 - 9\right)}^{2} + {\left(4 - 2\right)}^{2}} = \sqrt{16 + 4} = \sqrt{20} = 4.4721$ and

$c = \sqrt{{\left(5 - 6\right)}^{2} + {\left(4 - 0\right)}^{2}} = \sqrt{1 + 16} = \sqrt{17} = 4.1231$

Hence perimeter is $3.6056 + 4.4721 + 4.1231 = 12.2008$