# What is the perimeter of a triangle with sides 13/5, 31/5, and 33/5?

Mar 2, 2018

8$\frac{2}{5}$

#### Explanation:

add 1$\frac{3}{5}$ and 3$\frac{1}{5}$ together
4$\frac{4}{5}$
add 4$\frac{4}{5}$ and 3$\frac{3}{5}$ together
7$\frac{7}{5}$
simplify
8$\frac{2}{5}$

Mar 3, 2018

The perimeter of the triangle is $8 \frac{2}{5}$.

#### Explanation:

Determine the perimeter of a triangle with sides:

$1 \frac{3}{5} ,$ $3 \frac{1}{5} ,$ $3 \frac{3}{5}$

The perimeter of a triangle is the sum of the lengths of its three sides.

$P = 1 \frac{3}{5} + 3 \frac{1}{5} + 3 \frac{3}{5} = 7 \frac{7}{5}$

Convert $7 \frac{7}{5}$ to an improper fraction by multiplying the denominator by the whole number and adding the numerator, placing the result over the denominator.

$\frac{5 \times 7 + 7}{5} = \frac{42}{5}$

To determine the mixed fraction, divide the numerator by the denominator until you get a whole number with a remainder. (Use long division.)

$42 \div 5 = \text{8 r5}$

The whole number becomes the whole number of the fraction, the remainder becomes the numerator, and the denominator is $5$.

The mixed fraction is $8 \frac{2}{5}$.