# What is the perimeter of an isosceles triangle whose base is 16 cm and whose height is 15 cm?

Nov 21, 2015

$2 p = 50$

#### Explanation:

The height touches the midpoint of the basis.
Right triangle: ${\left(\frac{b}{2}\right)}^{2} + {h}^{2} = {L}^{2}$

${8}^{2} + {15}^{2} = {L}^{2} R i g h t a r r o w L = 17$

$2 p = L + L + b = 17 + 17 + 16$