What is the period and amplitude for #f(x)=3cos2x#?

1 Answer
May 14, 2015

You can "read" these information from your function:
1] The number multiplying the #cos# represents the AMPLITUE. So your #cos# oscillates between #+3# and #-3#;
2] The number multiplying the #x# in the argument allows you to evaluate the PERIOD as: #(period)=(2pi)/color(red)(2)=pi#. This means that your function needs the length #pi# to complete one oscillation. graph{3cos(2x) [-10, 10, -5, 5]}