What is the period and amplitude for #y= -1/2cos(3x+4pi/3)#?

1 Answer
May 30, 2018

#Amplitude = |A| = 1/2#

Period # = (2pi) / |B| = (2pi) / 3#

Explanation:

Standard form of the cos function is #y = A cos (Bx - C) + D#

Given #y = (1/2) cos (3x + color(crimson)((4pi)/3))#

#A = 1/2, B = 3, C = (4pi)/3#

#Amplitude = |A| = 1/2#

Period # = (2pi) / |B| = (2pi) / 3#

Phase Shift # = -C / B = ((4pi)/3) / 3 = (4pi)/9#

Vertical Shift = D = 0#