What is the period of $f (t) = cos 8 t$ $f(t)=cos 8 t$ ?

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What is the period of $f (t) = cos 8 t$ $f(t)=cos 8 t$ ?

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Answer 1 · 2018-06-19T17:50:27

The period is $\frac{π}{4}$ $pi/4$ . See explanation.

Explanation:

For any trigonometric function if the variable is multiplied by $a$ $a$ then the period is $a$ $a$ times smaller.

Here the basic function is $cos t$ $cost$ , so the basic period is $2 π$ $2pi$ . The coefficient by which $t$ $t$ is multiplied is $8$ $8$ , so the new period is:

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What is the period of $f (t) = cos 8 t$ $f(t)=cos 8 t$ ?

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Explanation:

$T = \frac{2 π}{8} = \frac{π}{4}$ $T=(2pi)/8=pi/4$

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What is the period of f(t)=cos8tf(t)=cos 8 t ?

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Explanation:

T=2π8=π4T=(2pi)/8=pi/4

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What is the period of $f (t) = cos 8 t$ $f(t)=cos 8 t$ ?

$T = \frac{2 π}{8} = \frac{π}{4}$ $T=(2pi)/8=pi/4$