# What is the period of f(t)=sin( 2 t -pi/4) ?

$P e r i o d = \pi$
Comparing with the General sine wave form$\left(f \left(t\right) = A \cdot \sin \left(B \cdot x + C\right) + D\right)$ Where A is amplitude; Period is $\frac{2 \cdot \pi}{B}$ ; Phase Shift is $- \frac{C}{B}$ and Vertical shift is $D$, Here A=1; B=2; C=-pi/4 ; D=0 So Period=$\frac{2 \cdot \pi}{2} \mathmr{and} P e r i o d = \pi$ [answer] graph{sin(2x-pi/4) [-10, 10, -5, 5]}