What is the period of #f(t)=sin( t -pi/2 ) #?

Question

3760 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-07-12T12:43:58

As detailed below.

Standard form of the sine function is

#y A sin (Bx - C) + D#

#f(t) = sin (t - pi/2)#

#A = 1, B = 1, C = pi/2, D = 0#

Amplitude #= |A| = 1#

Period #= (2pi)/|B| = (2pi)/1 = 2pi#

Phase Shift #= -C / B = -(pi/2) / (1) = -pi/2#, #color(crimson)(pi/2)# to the LEFT

Vertical Shift #D = 0#