What is the period of #f(theta)= sin 9t - cos 3 t #?

1 Answer
Shell
Sep 18, 2016

The period is #(2pi)/3#.

Explanation:

The period of #sin9t# is #(2pi)/9#.

The period of #cos3t# is #(2pi)/3#

The period of the composite function is the least common multiple of #(2pi)/9# and #(2pi)/3#.

#(2pi)/3=(6pi)/9#, thus #(2pi)/9# is a factor of (divides evenly into) #(2pi)/3# and the least common multiple of these two fractions is #(2pi)/3#

The period #=(2pi)/3#

Related questions
See all questions in Amplitude, Period and Frequency
Impact of this question
1481 views around the world
You can reuse this answer
Creative Commons License