Question

What is the period of `f(theta) = tan ( ( 12 theta)/7 )- sec ( ( 21 theta)/ 6 )`?

Answer 1

`28pi`

Explanation:

Period of `tan((12t)/7)`--> `(7pi)/12`
Period of `sec ((21t)/6) -> (12pi)/21 = (4pi)/7`
Least common multiple of (7pi)/12 and (4pi)/7 -->

`(7pi)/12` x (48) ---> 28pi
`(4pi)/7` x (49) ---> 28pi

Ans: Period of `f(t) = 28pi`