Question

What is the period of `f(theta) = tan ( ( 17 theta)/7 )- cos ( ( theta)/ 6 )`?

Answer 1

`84pi`

Explanation:

Period of `tan((17pi)/7)` --> `(7(pi))/17`
Period of `cos (t/6)` ---> `6(2pi) = 12pi`
Period of f(t) is least common multiple of `12pi and (7pi)/17`.

`(7pi)/17` ..... x (17)(12) ... --> `84pi`
`12pi`...............x (5) ....... --> `84pi`

Period of f(t) is `84pi`