What is the period of the function #y = cos 4x#?

1 Answer
Jul 11, 2016

#(pi)/2#

Explanation:

To find the period of the function,we can use the fact that the period is expressed as #(2pi)/|b|#, where #b# is the coefficient on the #x# term inside the function #cos(x)#, namely #cos(bx)#.

In this case, we have #y=acos(bx-c)+d#, where #a#, #c# and #d# are all #0#, so our equation becomes

#y = cos(4x) -> b = 4#, thus the period of the function is #(2pi)/(4) = (pi)/2#