# What is the pressure in a 10.0-L cylinder filled with 0.460 mol of nitrogen gas at a temperature of 314 K?

Approx. $1 \cdot a t m$. We use the Ideal Gas equation.........
$P = \frac{n R T}{V} = \frac{0.460 \cdot \cancel{m o l} \times \frac{0.0821 \cdot \cancel{L} \cdot a t m}{\cancel{K} \cdot \cancel{m o l}} \times 314 \cdot \cancel{K}}{10.0 \cdot \cancel{L}}$
$=$ ??atm