# What is the radius of the circle x^2 +y^2=7/4?

Dec 9, 2016

The radius is $= \frac{\sqrt{7}}{2} = 1.32$

#### Explanation:

The general equation of a circle is

${\left(x - a\right)}^{2} + {\left(y - b\right)}^{2} = {r}^{2}$

The center is $\left(a , b\right)$ and the radius is $= r$

Here,

${x}^{2} + {y}^{2} = {\left(\frac{\sqrt{7}}{2}\right)}^{2}$

This is a circle, center $\left(0 , 0\right)$ and radius $= \frac{\sqrt{7}}{2}$

graph{x^2+y^2=7/4 [-10, 10, -5, 5]}