What is the relationship between the pOH and the OH- ion concentration of a solution?

1 Answer
anor277
Dec 16, 2016

#pOH=-log_10[HO^-]#

Explanation:

And in aqueous solution, the acid base equilibrium operates:

#2H_2OrightleftharpoonsH_3O^(+) + HO^-#

At #298*K#, #K_w=10^-14=[HO^-][H_3O^+]#

And taking negative #log_10# of both sides.............

#-log_10K_w=-log_(10)10^-14=-log_10[HO^-]-log_10[H_3O^+]#

i.e. #14=pH+pOH#.

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