What is the set of numbers to which #-sqrt64# belong?

1 Answer
Oct 23, 2016

#-sqrt64=-8# is an integer

Explanation:

As #64# is a complete square, in fact it is #8^2# i.e. square of a natural number / rational number, we have

#-sqrt64=-8#, and it is

an integer, also a rational number# and may we say #a real number.

But normally one describes it as the smallest set of number system to which it can be ascribed. Hence, we can say

#-sqrt64=-8# is an integer