# What is the simplest radical form of sqrt(2 / 75)?

Ifound: $\frac{1}{15} \sqrt{6}$
$\sqrt{\frac{2}{75}} = \frac{\sqrt{2}}{\sqrt{75}} \cdot \frac{\sqrt{75}}{\sqrt{75}} = \frac{\sqrt{2} \sqrt{75}}{75} =$
$= \frac{\sqrt{2} \sqrt{3 \cdot 25}}{75} = \frac{5}{75} \sqrt{2} \sqrt{3} = \frac{1}{15} \sqrt{6}$