What is the simplest radical form of $sqrt116$ ?

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Answer 1 · 2017-02-17T13:22:04

$sqrt116=2sqrt29$

We try and split the number into the product of the factors where at least one of the numbers might be a perfect square.

Start by breaking it as you would for prime factorisation, and continue until you have perfect squares ( if they are there).

$sqrt116=sqrt(2xx58)=sqrt(2xx2xx29$

$sqrt(4xx29)=sqrt4 xxsqrt29$

Find any roots that you can.

$sqrt116=2sqrt29$

What is the simplest radical form of sqrt116sqrt116?