# What is the simplest radical form of sqrt116?

Feb 17, 2017

$\sqrt{116} = 2 \sqrt{29}$

#### Explanation:

We try and split the number into the product of the factors where at least one of the numbers might be a perfect square.

Start by breaking it as you would for prime factorisation, and continue until you have perfect squares ( if they are there).

sqrt116=sqrt(2xx58)=sqrt(2xx2xx29

$\sqrt{4 \times 29} = \sqrt{4} \times \sqrt{29}$

Find any roots that you can.

$\sqrt{116} = 2 \sqrt{29}$