What is the simplified radical form of #sqrt(24)#?

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Answer 1 · 2015-10-12T07:43:58

#=color(blue)(2sqrt6#

Simplifying this expression involves prime factorisation of #24#

#24= 2*2*2* 3#

(#2 and 3# are the prime factors of #24#)

So #sqrt(24)=sqrt(2*2*2*3)#

#=sqrt(2^2 *2*3)#

#=2*sqrt6#

#=color(blue)(2sqrt6#