What is the simplified radical form of #sqrt(45)#?

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Answer 1 · 2015-10-12T07:42:29

#=color(blue)(3sqrt5#

Simplifying this expression involves prime factorisation of #45#

#45= 3*3*5#

(#3 and 5# are the prime factors of #45#)

So #sqrt(45)=sqrt(3*3*5)#

#=sqrt(3^2 *5)#

#=3*sqrt5#

#=color(blue)(3sqrt5#