What is the simplified radical form of #sqrt(8)#?

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Answer 1 · 2015-10-12T07:41:03

#=color(blue)(2sqrt2#

Simplifying this expression involves prime factorisation of #8#

#8= 2*2*2#

(2 is the prime factor of #8#)

So #sqrt(8)=sqrt(2*2*2)#

#=sqrt(2^2 *2)#

#=2*sqrt2#

#=color(blue)(2sqrt2#