What is the simplified radical form of $\sqrt{96}$ $sqrt(96)$ ?

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Answer 1 · 2015-10-12T07:39:48

$= 4 \sqrt{6}$ $=color(blue)(4sqrt6$

Simplifying this expression involves prime factorisation of $96$ $96$

$96 = 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2 \cdot 3$ $96= 2*2*2*2*2*3$
( $2 and 3$ $2 and 3$ are the prime factors of $96$ $96$ )

So $\sqrt{96} = \sqrt{2 \cdot 2 \cdot 2 \cdot 2 \cdot 2 \cdot 3}$ $sqrt(96)=sqrt(2*2*2*2*2*3)$

$= \sqrt{2^{2} \cdot 2^{2} \cdot 2 \cdot 3}$ $=sqrt(2^2 *2^2 *2*3)$

$= 2 \cdot 2 \sqrt{6}$ $=2*2sqrt6$

$= 4 \sqrt{6}$ $=color(blue)(4sqrt6$

What is the simplified radical form of √96sqrt(96)?