# What is the simplified radical form of sqrt(96)?

Oct 12, 2015

#### Answer:

=color(blue)(4sqrt6

#### Explanation:

Simplifying this expression involves prime factorisation of $96$

$96 = 2 \cdot 2 \cdot 2 \cdot 2 \cdot 2 \cdot 3$
($2 \mathmr{and} 3$ are the prime factors of $96$)

So $\sqrt{96} = \sqrt{2 \cdot 2 \cdot 2 \cdot 2 \cdot 2 \cdot 3}$

$= \sqrt{{2}^{2} \cdot {2}^{2} \cdot 2 \cdot 3}$

$= 2 \cdot 2 \sqrt{6}$

=color(blue)(4sqrt6