# What is the slope-intercept form of the line passing through  (-4, 1)  and (4,2) ?

Mar 28, 2017

$y = \frac{1}{8} x + \frac{3}{2}$

#### Explanation:

If two points are know we can find the eqn as follows:

$\text{given "(x_1,y_1)" } \left({x}_{2} , {y}_{2}\right)$

$\text{eqn. " } \frac{y - {y}_{1}}{{y}_{2} - {y}_{1}} = \frac{x - {x}_{1}}{{x}_{2} - {x}_{1}}$

we have$\text{ " (x_1,y_1)=(-4,1)" } \left({x}_{2} , {y}_{2}\right) = \left(4 , 2\right)$

$\frac{y - 1}{2 - 1} = \frac{x - - 4}{4 - - 4}$

$\frac{y - 1}{1} = \frac{x + 4}{4 + 4} = \frac{x + 4}{8}$

$y - 1 = \frac{1}{8} x + \frac{1}{2}$

$y = \frac{1}{8} x + \frac{3}{2}$

$y = \frac{1}{8} x + \frac{3}{2}$