# What is the slope of any line perpendicular to the line passing through (-24,19) and (-8,15)?

Jul 22, 2016

Slope of desired line is $4$.

#### Explanation:

Slope of a line joining $\left({x}_{1} , {y}_{1}\right)$ and $\left({x}_{2} , {y}_{2}\right)$ is given by

$\frac{{y}_{2} - {y}_{1}}{{x}_{2} - {x}_{1}}$

Hence, slope the line passing through (−24,19) and (−8,15) is $\frac{15 - 19}{- 8 - \left(- 24\right)} = - \frac{4}{16} = - \frac{1}{4}$.

As product of slopes two perpendicular lines is $- 1$, slope of desired line will be $\frac{- 1}{- \frac{1}{4}} = - 1 \times - 4 = 4$.

Jul 22, 2016

Slope of desired line is $4$.

#### Explanation:

Slope of a line joining $\left({x}_{1} , {y}_{1}\right)$ and $\left({x}_{2} , {y}_{2}\right)$ is given by

$\frac{{y}_{2} - {y}_{1}}{{x}_{2} - {x}_{1}}$

Hence, slope the line passing through (−24,19) and (−8,15) is $\frac{15 - 19}{- 8 - \left(- 24\right)} = - \frac{4}{16} = - \frac{1}{4}$.

As product of slopes two perpendicular lines is $- 1$, slope of desired line will be $\frac{- 1}{- \frac{1}{4}} = - 1 \times - 4 = 4$.