What is the slope of any line perpendicular to the line passing through #(-24,19)# and #(-8,15)#?

2 Answers
Jul 22, 2016

Answer:

Slope of desired line is #4#.

Explanation:

Slope of a line joining #(x_1,y_1)# and #(x_2,y_2)# is given by

#(y_2-y_1)/(x_2-x_1)#

Hence, slope the line passing through (−24,19) and (−8,15) is #(15-19)/(-8-(-24))=-4/16=-1/4#.

As product of slopes two perpendicular lines is #-1#, slope of desired line will be #(-1)/(-1/4)=-1xx-4=4#.

Jul 22, 2016

Answer:

Slope of desired line is #4#.

Explanation:

Slope of a line joining #(x_1,y_1)# and #(x_2,y_2)# is given by

#(y_2-y_1)/(x_2-x_1)#

Hence, slope the line passing through (−24,19) and (−8,15) is #(15-19)/(-8-(-24))=-4/16=-1/4#.

As product of slopes two perpendicular lines is #-1#, slope of desired line will be #(-1)/(-1/4)=-1xx-4=4#.