# What is the solution set for #2 -sqrt(x+3) =6#?

##### 1 Answer

Aug 19, 2015

#### Answer:

#### Explanation:

As it is written, this equation has **no solution among real numbers**, and here's why that is the case.

For *real numbers*, you can only take the square root of a *positive number*, and the result will **always** be another **positive** number.

#color(blue)(sqrt(x) >=0", "(AA)x in [0, + oo))#

Rearrange the equation to isolate the square root on one side

#-sqrt(x+3) = 4#

#sqrt(x+3) = -4#

Since the square root must always be a positive number, your equation does not have a valid solution among real numbers.

#sqrt(x+3) color(red)(!=) -4#