# What is the solution set of (h-6)^2=400?

Apr 10, 2018

26.

#### Explanation:

You are solving for h here, so you would first square root both sides of the equation to get

h-6=20.

Then you add 6 to both sides to get

h=26.

Apr 10, 2018

The two solutions are $h = 26$ and $h = - 14$.

#### Explanation:

You can square root both sides to cancel the power:

${\left(h - 6\right)}^{2} = 400$

$\textcolor{red}{\sqrt{\textcolor{b l a c k}{{\left(h - 6\right)}^{2}}}} = \textcolor{red}{\sqrt{\textcolor{b l a c k}{400}}}$

$h - 6 = \textcolor{red}{\sqrt{\textcolor{b l a c k}{400}}}$

$h - 6 = \pm 20$

Solve each equation separately for two solutions:

$h - 6 = 20$

$h = 26$

And:

$h - 6 = - 20$

$h = - 14$

Those are the two solutions. Hope this helped!