What is the speed of an object that travels from #( 1, -2, 3 ) # to #( -5, 6, 7 ) # over #4 s#?

1 Answer
Jan 25, 2016

Answer:

#2.693m//s#

Explanation:

The distance between the 2 given 3-dimensional points may be found from the normal Euclidean metric in #RR^3# as follows :

#x=d( (1,-2,3);(-5,6,7) )=sqrt((1-(-5))^2+(-2-6)^2+(3-7)^2)#

#=sqrt(36+64+16#

#=sqrt116m# , (Assuming the SI units are used)

Therefore the speed of the object by definition would be the rate of change in distance and given by

#v=x/t=sqrt116/4=2.693m//s#.