What is the $\sqrt{336}$ $sqrt336$ in simplest radical form?

Question

4108 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-05T21:09:06

$4 \sqrt{21}$ $4sqrt(21)$

Split 336 into prime factors,
$\sqrt{336} = \sqrt{2^{4} \cdot 3 \cdot 7}$ $sqrt(336) = sqrt(2^4*3*7)$

Separate the $2^{4}$ $2^4$ part,
$\sqrt{336} = \sqrt{2^{4}} \cdot \sqrt{3 \cdot 7}$ $sqrt(336) = sqrt(2^4)*sqrt(3*7)$

Simplify,
$\sqrt{336} = 4 \cdot \sqrt{21}$ $sqrt(336) = 4*sqrt(21)$

What is the √336sqrt336 in simplest radical form?