# What is the square root of 6 in simplest radical form?

$\sqrt{12}$ can be simplified because $12$ is divisible by $4$ -- a perfect square.
$\sqrt{12} = \sqrt{4 \times 3} = \sqrt{4} \times \sqrt{3} = 2 \sqrt{3}$
$\sqrt{250}$ can be simplified because $250$ is divisible by $25$
$\sqrt{250} = \sqrt{25 \times 10} = \sqrt{25} \times \sqrt{10} = 5 \sqrt{10}$
But $6$ is not divisible by a perfect square, so $\sqrt{6}$ cannt be simpified further.