# What is the square root of 6 in simplest radical form?

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Jim H Share
Apr 15, 2015

The square root pf a number can be simplified only if the number is divisible by a perfect square (other than 1).

$\sqrt{12}$ can be simplified because $12$ is divisible by $4$ -- a perfect square.
$\sqrt{12} = \sqrt{4 \times 3} = \sqrt{4} \times \sqrt{3} = 2 \sqrt{3}$

$\sqrt{250}$ can be simplified because $250$ is divisible by $25$
$\sqrt{250} = \sqrt{25 \times 10} = \sqrt{25} \times \sqrt{10} = 5 \sqrt{10}$

But $6$ is not divisible by a perfect square, so $\sqrt{6}$ cannt be simpified further.

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