# What is the standard form of a polynomial  (-3h - 4)(4h - 3) ?

Apr 23, 2017

See the entire solution process below:

#### Explanation:

To convert this expression to the standard form we must multiply the two terms. To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

$\left(\textcolor{red}{- 3 h} - \textcolor{red}{4}\right) \left(\textcolor{b l u e}{4 h} - \textcolor{b l u e}{3}\right)$ becomes:

$\left(\textcolor{red}{- 3 h} \times \textcolor{b l u e}{4 h}\right) + \left(\textcolor{red}{3 h} \times \textcolor{b l u e}{3}\right) - \left(\textcolor{red}{4} \times \textcolor{b l u e}{4 h}\right) + \left(\textcolor{red}{4} \times \textcolor{b l u e}{3}\right)$

$- 12 {h}^{2} + 9 h - 16 h + 12$

We can now combine like terms:

$- 12 {h}^{2} + \left(9 - 16\right) h + 12$

$- 12 {h}^{2} + \left(- 7\right) h + 12$

$- 12 {h}^{2} - 7 h + 12$