What is the standard form of $f(x)=(x-1)(x-9)-(2x-1)^2$ ?

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Answer 1 · 2016-02-21T10:29:19

Standard form is $f(x)=−3x^2−6x+8$

To find the standard form of $f(x)=(x−1)(x−9)−(2x−1)^2$ , we first simplify this

$f(x)=(x−1)(x−9)−(2x−1)^2$

= $(x−1)x−(x−1)9−((2x)^2−2*2x*1+1^2)$

= $(x^2−x−9x+9)−(4x^2−4x*1+1)$ , now grouping them

= $(x^2−4x^2−10x+4x+9-1)$

= $−3x^2−6x+8$

What is the standard form of f(x)=(x-1)(x-9)-(2x-1)^2 f(x)=(x-1)(x-9)-(2x-1)^2 ?