# What is the standard form of the equation of a circle given points: (7,-1), (11,-5), (3,-5)?

##### 1 Answer

#### Answer:

Standard form of circle is

#### Explanation:

Let the equation of circle be

**......(1)**

**...(2)**

**......(3)**

Subtracting (1) from (2) we get

**......(A)**

and subtracting (3) from (2) we get

putting this in (A), we have

and putting values of

andequation of circle is

and its centre is

and standard form of circle is

graph{x^2+y^2-14x+10y+58=0 [-3.08, 16.92, -9.6, 0.4]}