# What is the standard form of the equation of a circle with a center (4, 1) and a radius of 6?

Mar 29, 2018

${\left(x - 4\right)}^{2} + {\left(y - 1\right)}^{2} = {6}^{2}$

#### Explanation:

If a circle has its centre at the point (a, b) and a radius r, then the standard form of the equation of a circle is:

${\left(x - a\right)}^{2} + {\left(y - b\right)}^{2} = {r}^{2}$

In this case, then:

${\left(x - 4\right)}^{2} + {\left(y - 1\right)}^{2} = {6}^{2}$