What is the standard form of #y= (x - 8) (x+6) #?

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Answer 1 · 2016-06-27T06:50:58

#y=x^2-2x-48#

It is a quadratic function and standard form of quadratic function is

#y=ax^2+bx+c#

To convert, let us multiply the RHS as follows:

#y=(x-8)(x+6)#

= #x(x+6)-8(x+6)#

= #x^2+6x-8x-48#

= #x^2-2x-48#