# What is the surface area of the solid created by revolving #f(x) = 2x^2-x+5 , x in [1,2]# around the x axis?

##### 1 Answer

#### Explanation:

The surface area of the solid created by revolving a positive function,

The derivation of this is fairly simple. It involves the surface area of a frustrum which is

Anyways, in the case of this problem, the first thing to notice is that

at this point I would use a calculator to find the value of this integral which would end up being the answer.