What is the surface area of the solid created by revolving #f(x) = (3x-1)^2 , x in [1,3]# around the x axis?
The question seems rather odd.
The formula for computing the surface area is
In your case,
This integral yields a very complicate solution, which I don't believe your homework could ever ask for. For completeness sake, you can check it from WolframAlpha