What is the surface area of the solid created by revolving #f(x)=-sqrtx/e^x# over #x in [0,1]# around the x-axis?
I got as far as the definite integral but then I got stuck at the solution of the integral....probably there is a mistake or there is an easier way...
I considered the function and the rotation:
then I used the standard technique:
giving the expression of the surface area
which I am not able to solve!!!