# What is the the vertex of y = 6(x - 2)^2 ­- 8?

Feb 25, 2016

$\text{Vertex} \to \left(x , y\right) \to \left(2 , - 8\right)$

#### Explanation:

The equation in this vertex form gives you the value of x for the vertex.

Consider the -2 from $\left(x - 2\right)$

Apply $\left(- 1\right) \times \left(- 2\right) = + 2$

$\textcolor{b l u e}{{x}_{\text{vertex}} = + 2}$

Substitute $x = 2$ into the equation to find ${y}_{\text{vertex}}$

${y}_{\text{vertex}} = 6 {\left(2 - 2\right)}^{2} - 8$

${y}_{\text{vertex}} = 6 {\left(0\right)}^{2} - 8$

color(blue)(y_("vertex") = -8
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color(green)("Vertex"->(x,y)->(2,-8)