# What is the the vertex of y =(x - 16)^2 + 40 ?

##### 1 Answer
Dec 23, 2015

$\left(16 , 40\right)$

#### Explanation:

The equation is already in vertex form so it is possible to see that the value is at its minimum when the squared factor is zero. this occurs when $x = 16$ and at that point $y = 40$