# What is the the vertex of y = x^2+12x+22 ?

$y = {\left(x + 6\right)}^{2} - 24 \text{ Vertex is at} \left(- 6 , - 24\right)$
$y = {x}^{2} + 12 x + \textcolor{red}{36} + 12 - \textcolor{red}{36}$
$y = {\left(x + 6\right)}^{2} - 24$