What is the the vertex of #y = x^2-4x+3#?

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Answer 1 · 2017-02-26T09:19:35

#(2, –1)#

The vertex formula is #(-b)/(2a)#

In this equation, #a = 1#, #b = –4#, and #c = 3#.

Plugging the numbers into the equation, you should get

#(4)/(2(1)) = (4)/(2) = 2#

2 is the #x# value of the equation. If you plug it into the equation, you'll end up with the #y# value.

#y = (2)^2 – 4(2) + 3#
#y = –1#

So the vertex is #(2, –1)#