What is the the vertex of #y =x^2+8x-3 #? Algebra Quadratic Equations and Functions Quadratic Functions and Their Graphs 1 Answer Binayaka C. May 22, 2016 Vertex is at # -4, -19# Explanation: #y=x^2+8x-3 = (x^2+8x+16) -16-3 =(x+4)^2 -19 :.#Vertex is at # -4, -19# graph{x^2+8x-3 [-80, 80, -40, 40]}[Ans] Answer link Related questions What are the important features of the graphs of quadratic functions? What do quadratic function graphs look like? How do you find the x intercepts of a quadratic function? How do you determine the vertex and direction when given a quadratic function? How do you determine the range of a quadratic function? What is the domain of quadratic functions? How do you find the maximum or minimum of quadratic functions? How do you graph #y=x^2-2x+3#? How do you know if #y=16-4x^2# opens up or down? How do you find the x-coordinate of the vertex for the graph #4x^2+16x+12=0#? See all questions in Quadratic Functions and Their Graphs Impact of this question 1296 views around the world You can reuse this answer Creative Commons License