What is the the vertex of y = (x + 3)^2-9 ?

1 Answer

This has a vertex at $x = - 3$ hence its vertex is at $\left(- 3 , - 9\right)$

The quadratic equation in form $y = a \cdot {\left(x - h\right)}^{2} + k$ has a vertex at

$\left(h , k\right)$