What is the the vertex of #y = (x -3)^2+9x-17 #?
Vertex is at (-3/2,-41/4)
This is the equation of Parabola y= x^2-6x+9+9x-17 or y =x^2+3x-8
which can be written is y=(x+3/2)^2 -8 -9/4 or y = (x+3/2)^2-(41/4)
We know the equation of Parabola as y=a(x-h)^2 +k ; then the vertex is (h,k) ; So here h = -3/2 and k= -41/4 Therefore the vertex is at (-3/2,-41/4) [Answer]