Question

What is the the vertex of `y=(x - 8)^2 + 16x+70`?

Answer 1

Minimum (0,134)

Explanation:

expand the bracket

`y=x^2-16x+64+16x+70`

`y=x^2+134`

Use `(-b)/(2a)`

`=>0/2=0`

when `x=0, y=134`

vertex is (0,134)