If your velocity is
v=5.0 "furlongs"/"fortnight"v=5.0furlongsfortnight
then we'll need some conversion factors. After a quick Google search, I discovered that
1xx"furlong" = 220 " yards"1×furlong=220 yards and 1xx"fortnight"=14 " days"1×fortnight=14 days
So let's get to converting! First, we may convert time:
v=5.0 "furlongs"/"fortnight"xx(1 " fortnight")/(14 " days")v=5.0furlongsfortnight×1 fortnight14 days
xx(1 " day")/(24 " hours")xx(1 " hour")/(60 " min")xx(1 " min")/(60 " sec")=4.13xx10^-6 "furlongs"/"sec"×1 day24 hours×1 hour60 min×1 min60 sec=4.13×10−6furlongssec
Second, converting distance, we have
v=4.13xx10-6 "furlongs"/"sec"xx(220 " yards")/(1 " furlong")xx(3 " ft")/(1 " yard")v=4.13×10−6furlongssec×220 yards1 furlong×3 ft1 yard
xx(1 " m")/(3.281 " ft")=8.32xx10^-4 "m"/"sec"×1 m3.281 ft=8.32×10−4msec
