What is the velocity #5.0 " furlongs"/"fortnight"# in #"meters"/"second"#?

1 Answer
Mar 20, 2016

Answer:

#8.32xx10^-4 "m"/"sec"#

Explanation:

If your velocity is

#v=5.0 "furlongs"/"fortnight"#

then we'll need some conversion factors. After a quick Google search, I discovered that

#1xx"furlong" = 220 " yards"# and #1xx"fortnight"=14 " days"#

So let's get to converting! First, we may convert time:

#v=5.0 "furlongs"/"fortnight"xx(1 " fortnight")/(14 " days")#
#xx(1 " day")/(24 " hours")xx(1 " hour")/(60 " min")xx(1 " min")/(60 " sec")=4.13xx10^-6 "furlongs"/"sec"#

Second, converting distance, we have
#v=4.13xx10-6 "furlongs"/"sec"xx(220 " yards")/(1 " furlong")xx(3 " ft")/(1 " yard")#
#xx(1 " m")/(3.281 " ft")=8.32xx10^-4 "m"/"sec"#